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Question - 2 What are the major steps of a Chaitin-Briggs (global, bottom-up) register allocator?repeated if instructions are spilled?range that includes all program point from that deï¬nition up to the last use of that deï¬nition. register allocator? of the deï¬nitions of some variable (or virtual register) and a subset of the uses of that virtual register, such that any deï¬nition of that variable that reaches a use in the live range's "use set" will be included in that live range's "deï¬nition set" and "use set" will include every use that can be reached from a deï¬nition in that live range's "use set". Each deï¬nition of a variable and each use of a variable may appear only
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in a single live range. independently "colored" with a register. What problem would arise if a deï¬nition can reach a use that belongs to a different live range? a way of renaming variables (or virtual registers), similar to the way SSA renames variables. If one replaces each deï¬nition/use of a variable (or virtual register) with the live range to which it belongs, one can then compute for each program location, which live ranges are live, by using the LIVEOUT dataflow analysis to get global information and then examining each block starting at the bottom of the block using the LIVEOUT information. How is this process modiï¬ed to determine whether two live ranges interfere? ...Read Less
Solution Preview - otation Used: -
GI: Interference Graph, where GI = (NI, EI)
R: Number of Registers (R colours)
N: Node or Vertex in the Graph GI
While there exists vertices with < R neighbours in GI 1.1 Pick any vertex N (degree) N < R and push it onto the stack 1.2 Remove that vertex and all the associated edges with it from GI
If GI is non-e
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